We kunnen een breuk herhaaldelijk met zichzelf vermenigvuldigen.

$$\begin{array}{rclrc}\left(\frac{\blue2}{\green3}\right)^\orange0&&&=\frac{\blue2^\orange0}{\green3^\orange0}&=1\\\left(\frac{\blue2}{\green3}\right)^\orange1&=&\frac{\blue2}{\green3}&= \frac{\blue2^\orange1}{\green3^\orange1}&=\frac{2}{3}\\\left(\frac{\blue2}{\green3}\right)^\orange2&=&\frac{\blue2}{\green3}\times \frac{\blue2}{\green3}&=\frac{\blue2^\orange2}{\green3^\orange2} &=\frac{4}{9}\\\left(\frac{\blue2}{\green3}\right)^\orange3&=&\frac{\blue2}{\green3} \times \frac{\blue2}{\green3} \times \frac{\blue2}{\green3}&=\frac{\blue2^\orange3}{\green3^\orange3}&=\frac{8}{27} \\ \left(\frac{\blue2}{\green3}\right)^\orange4&=&\frac{\blue2}{\green3} \times \frac{\blue2}{\green3} \times \frac{\blue2}{\green3} \times \frac{\blue2}{\green3}&=\frac{\blue2^\orange4}{\green3^\orange4}&=\frac{16}{81}\end{array}$$

In het algemeen geldt:

De macht van een breuk is de macht van de $\blue{\textit{teller}}$ gedeeld door de macht van de $\green{\textit{noemer}}$.

Voorbeelden

$$\begin{array}{rcl}\left(\frac{\blue1}{\green5}\right)^\orange4&=&\frac{\blue1^\orange4}{\green5^\orange4} \\ &=& \frac{1}{625} \\ \\ \left(\frac{\blue3}{\green4}\right)^\orange2&=&\frac{\blue3^\orange2}{\green4^\orange2}\\ &=& \frac{9}{16}\\ \\ \left(-\frac{\blue1}{\green3}\right)^\orange4&=&\frac{\left(\blue{-1}\right)^\orange4}{\green3^\orange4}\\ &=& \frac{1}{81}\\ \\ \end{array}$$